Base | Representation |
---|---|
bin | 10010111110110110001… |
… | …011011010010101010011 |
3 | 11121200222002001210000111 |
4 | 102332312023122111103 |
5 | 132332433433113233 |
6 | 2435125250502151 |
7 | 163146013051651 |
oct | 22766613322523 |
9 | 4550862053014 |
10 | 1304431535443 |
11 | 46322a660383 |
12 | 190983594957 |
13 | 9601324c26a |
14 | 471c5d51dd1 |
15 | 23de7edcacd |
hex | 12fb62da553 |
1304431535443 has 2 divisors, whose sum is σ = 1304431535444. Its totient is φ = 1304431535442.
The previous prime is 1304431535299. The next prime is 1304431535497. The reversal of 1304431535443 is 3445351344031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1304431535443 - 225 = 1304397981011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1304431535396 and 1304431535405.
It is not a weakly prime, because it can be changed into another prime (1304431335443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652215767721 + 652215767722.
It is an arithmetic number, because the mean of its divisors is an integer number (652215767722).
Almost surely, 21304431535443 is an apocalyptic number.
1304431535443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304431535443 is an equidigital number, since it uses as much as digits as its factorization.
1304431535443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 1304431535443 its reverse (3445351344031), we get a palindrome (4749782879474).
The spelling of 1304431535443 in words is "one trillion, three hundred four billion, four hundred thirty-one million, five hundred thirty-five thousand, four hundred forty-three".
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