Base | Representation |
---|---|
bin | 10010111110110110001… |
… | …011011010010110100001 |
3 | 11121200222002001210010101 |
4 | 102332312023122112201 |
5 | 132332433433114041 |
6 | 2435125250502401 |
7 | 163146013052122 |
oct | 22766613322641 |
9 | 4550862053111 |
10 | 1304431535521 |
11 | 46322a660444 |
12 | 190983594a01 |
13 | 9601324c2ca |
14 | 471c5d52049 |
15 | 23de7edcb31 |
hex | 12fb62da5a1 |
1304431535521 has 2 divisors, whose sum is σ = 1304431535522. Its totient is φ = 1304431535520.
The previous prime is 1304431535507. The next prime is 1304431535567. The reversal of 1304431535521 is 1255351344031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1277948855296 + 26482680225 = 1130464^2 + 162735^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304431535521 - 211 = 1304431533473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304431536521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652215767760 + 652215767761.
It is an arithmetic number, because the mean of its divisors is an integer number (652215767761).
Almost surely, 21304431535521 is an apocalyptic number.
It is an amenable number.
1304431535521 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304431535521 is an equidigital number, since it uses as much as digits as its factorization.
1304431535521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 1304431535521 its reverse (1255351344031), we get a palindrome (2559782879552).
The spelling of 1304431535521 in words is "one trillion, three hundred four billion, four hundred thirty-one million, five hundred thirty-five thousand, five hundred twenty-one".
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