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1304434103143 = 10611229438363
BaseRepresentation
bin10010111110110110010…
…101001101001101100111
311121200222020220020020111
4102332312111031031213
5132332440112300033
62435125421513451
7163146043634653
oct22766625151547
94550866806214
101304434103143
11463231054546
12190984412887
139601393ac02
14471c641da63
1523de83487cd
hex12fb654d367

1304434103143 has 4 divisors (see below), whose sum is σ = 1305663542568. Its totient is φ = 1303204663720.

The previous prime is 1304434103113. The next prime is 1304434103149. The reversal of 1304434103143 is 3413014344031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304434103143 - 25 = 1304434103111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304434103149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 614718121 + ... + 614720242.

It is an arithmetic number, because the mean of its divisors is an integer number (326415885642).

Almost surely, 21304434103143 is an apocalyptic number.

1304434103143 is a deficient number, since it is larger than the sum of its proper divisors (1229439425).

1304434103143 is a wasteful number, since it uses less digits than its factorization.

1304434103143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1229439424.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1304434103143 its reverse (3413014344031), we get a palindrome (4717448447174).

The spelling of 1304434103143 in words is "one trillion, three hundred four billion, four hundred thirty-four million, one hundred three thousand, one hundred forty-three".

Divisors: 1 1061 1229438363 1304434103143