Base | Representation |
---|---|
bin | 111100101111100010… |
… | …0011010101001100110 |
3 | 110110200212102101202200 |
4 | 1321133010122221212 |
5 | 4114122131342014 |
6 | 135531455515330 |
7 | 12265344544242 |
oct | 1713704325146 |
9 | 413625371680 |
10 | 130444012134 |
11 | 50359276007 |
12 | 21345528b46 |
13 | c3bab85bc7 |
14 | 6456449422 |
15 | 35d6d1ca09 |
hex | 1e5f11aa66 |
130444012134 has 12 divisors (see below), whose sum is σ = 282628692996. Its totient is φ = 43481337372.
The previous prime is 130444012093. The next prime is 130444012141. The reversal of 130444012134 is 431210444031.
130444012134 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 440 + 1 + 213 + 4 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 130444012098 and 130444012107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3623444764 + ... + 3623444799.
It is an arithmetic number, because the mean of its divisors is an integer number (23552391083).
Almost surely, 2130444012134 is an apocalyptic number.
130444012134 is an abundant number, since it is smaller than the sum of its proper divisors (152184680862).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130444012134 is a wasteful number, since it uses less digits than its factorization.
130444012134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7246889571 (or 7246889568 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 130444012134 its reverse (431210444031), we get a palindrome (561654456165).
The spelling of 130444012134 in words is "one hundred thirty billion, four hundred forty-four million, twelve thousand, one hundred thirty-four".
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