13044401341 has 4 divisors (see below), whose sum is σ = 13730948800. Its totient is φ = 12357853884.

The previous prime is 13044401329. The next prime is 13044401387. The reversal of 13044401341 is 14310444031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14310444031 = 13 ⋅1100803387.

It is a cyclic number.

It is not a de Polignac number, because 13044401341 - 2³³ = 4454466749 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044401311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343273701 + ... + 343273738.

It is an arithmetic number, because the mean of its divisors is an integer number (3432737200).

Almost surely, 2^13044401341 is an apocalyptic number.

It is an amenable number.

13044401341 is a deficient number, since it is larger than the sum of its proper divisors (686547459).

13044401341 is an equidigital number, since it uses as much as digits as its factorization.

13044401341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 686547458.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044401341 its reverse (14310444031), we get a palindrome (27354845372).

The spelling of 13044401341 in words is "thirteen billion, forty-four million, four hundred one thousand, three hundred forty-one".