Search a number
-
+
130444035 = 3547185027
BaseRepresentation
bin1111100011001…
…10101100000011
3100002110020120120
413301212230003
5231343202120
620535511323
73142520211
oct761465403
9302406516
10130444035
11676a5597
1237828543
1321042927
1413477cb1
15b6ba140
hex7c66b03

130444035 has 16 divisors (see below), whose sum is σ = 213152256. Its totient is φ = 68089568.

The previous prime is 130444031. The next prime is 130444037. The reversal of 130444035 is 530444031.

It is a cyclic number.

It is not a de Polignac number, because 130444035 - 22 = 130444031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130443996 and 130444014.

It is not an unprimeable number, because it can be changed into a prime (130444031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91809 + ... + 93218.

It is an arithmetic number, because the mean of its divisors is an integer number (13322016).

Almost surely, 2130444035 is an apocalyptic number.

130444035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130444035 is a deficient number, since it is larger than the sum of its proper divisors (82708221).

130444035 is a wasteful number, since it uses less digits than its factorization.

130444035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185082.

The product of its (nonzero) digits is 2880, while the sum is 24.

The square root of 130444035 is about 11421.2098746149. The cubic root of 130444035 is about 507.1558134437.

Adding to 130444035 its reverse (530444031), we get a palindrome (660888066).

The spelling of 130444035 in words is "one hundred thirty million, four hundred forty-four thousand, thirty-five".

Divisors: 1 3 5 15 47 141 235 705 185027 555081 925135 2775405 8696269 26088807 43481345 130444035