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1304441031034 = 2957916808787
BaseRepresentation
bin10010111110110110101…
…111101000100101111010
311121200222201221012112001
4102332312233220211322
5132332443400443114
62435130230211214
7163146156550621
oct22766657504572
94550881835461
101304441031034
11463234a56579
121909867b3b0a
13960151c535b
14471c73046b8
1523de8c66374
hex12fb6be897a

1304441031034 has 8 divisors (see below), whose sum is σ = 1956682260288. Its totient is φ = 652213610940.

The previous prime is 1304441031007. The next prime is 1304441031073. The reversal of 1304441031034 is 4301301444031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13044410310342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304441030993 and 1304441031011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3212812 + ... + 3595975.

It is an arithmetic number, because the mean of its divisors is an integer number (244585282536).

Almost surely, 21304441031034 is an apocalyptic number.

1304441031034 is a deficient number, since it is larger than the sum of its proper divisors (652241229254).

1304441031034 is an equidigital number, since it uses as much as digits as its factorization.

1304441031034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6904580.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1304441031034 its reverse (4301301444031), we get a palindrome (5605742475065).

The spelling of 1304441031034 in words is "one trillion, three hundred four billion, four hundred forty-one million, thirty-one thousand, thirty-four".

Divisors: 1 2 95791 191582 6808787 13617574 652220515517 1304441031034