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1304443534003 = 23531070093137
BaseRepresentation
bin10010111110110110111…
…001001011101010110011
311121200222220122100221121
4102332312321023222303
5132333000021042003
62435130400003111
7163146220044121
oct22766671135263
94550886570847
101304443534003
11463236406045
12190987600497
13960158906bc
14471c7796911
1523de90accbd
hex12fb6e4bab3

1304443534003 has 8 divisors (see below), whose sum is σ = 1386840706848. Its totient is φ = 1224186547584.

The previous prime is 1304443534001. The next prime is 1304443534021. The reversal of 1304443534003 is 3004353444031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1304443534003 - 21 = 1304443534001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1304443534003.

It is not an unprimeable number, because it can be changed into a prime (1304443534001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535045350 + ... + 535047787.

It is an arithmetic number, because the mean of its divisors is an integer number (173355088356).

Almost surely, 21304443534003 is an apocalyptic number.

1304443534003 is a deficient number, since it is larger than the sum of its proper divisors (82397172845).

1304443534003 is a wasteful number, since it uses less digits than its factorization.

1304443534003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1070093213.

The product of its (nonzero) digits is 103680, while the sum is 34.

Adding to 1304443534003 its reverse (3004353444031), we get a palindrome (4308796978034).

The spelling of 1304443534003 in words is "one trillion, three hundred four billion, four hundred forty-three million, five hundred thirty-four thousand, three".

Divisors: 1 23 53 1219 1070093137 24612142151 56714936261 1304443534003