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1304502230953 is a prime number
BaseRepresentation
bin10010111110111010011…
…001000101111110101001
311121201011000002111000201
4102332322121011332221
5132333110032342303
62435140254032201
7163150532003215
oct22767231057651
94551130074021
101304502230953
11463266556a19
121909a31a8661
1396024aa251c
14471d14b5945
1523dee30481d
hex12fba645fa9

1304502230953 has 2 divisors, whose sum is σ = 1304502230954. Its totient is φ = 1304502230952.

The previous prime is 1304502230939. The next prime is 1304502230987. The reversal of 1304502230953 is 3590322054031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1275085864809 + 29416366144 = 1129197^2 + 171512^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304502230953 - 217 = 1304502099881 is a prime.

It is a super-2 number, since 2×13045022309532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1304502930953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652251115476 + 652251115477.

It is an arithmetic number, because the mean of its divisors is an integer number (652251115477).

Almost surely, 21304502230953 is an apocalyptic number.

It is an amenable number.

1304502230953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304502230953 is an equidigital number, since it uses as much as digits as its factorization.

1304502230953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

Adding to 1304502230953 its reverse (3590322054031), we get a palindrome (4894824284984).

The spelling of 1304502230953 in words is "one trillion, three hundred four billion, five hundred two million, two hundred thirty thousand, nine hundred fifty-three".