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13046733841 is a prime number
BaseRepresentation
bin11000010011010010…
…10101110000010001
31020200020201202020111
430021221111300101
5203204430440331
65554340441321
7641211256621
oct141151256021
936606652214
1013046733841
1155955a5269
1226413a9241
1312cbc8556b
148baa52881
155155d3db1
hex309a55c11

13046733841 has 2 divisors, whose sum is σ = 13046733842. Its totient is φ = 13046733840.

The previous prime is 13046733823. The next prime is 13046733853. The reversal of 13046733841 is 14833764031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11582064400 + 1464669441 = 107620^2 + 38271^2 .

It is a cyclic number.

It is not a de Polignac number, because 13046733841 - 25 = 13046733809 is a prime.

It is a super-2 number, since 2×130467338412 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13046733794 and 13046733803.

It is not a weakly prime, because it can be changed into another prime (13046743841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6523366920 + 6523366921.

It is an arithmetic number, because the mean of its divisors is an integer number (6523366921).

Almost surely, 213046733841 is an apocalyptic number.

It is an amenable number.

13046733841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13046733841 is an equidigital number, since it uses as much as digits as its factorization.

13046733841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 40.

The spelling of 13046733841 in words is "thirteen billion, forty-six million, seven hundred thirty-three thousand, eight hundred forty-one".