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130473036481 is a prime number
BaseRepresentation
bin111100110000011001…
…1001000101011000001
3110110202220000222200111
41321200303020223001
54114202044131411
6135534413551321
712266146340314
oct1714063105301
9413686028614
10130473036481
115037369a477
12213531a5541
13c3c3ba8a88
14645a24297b
1535d9652721
hex1e60cc8ac1

130473036481 has 2 divisors, whose sum is σ = 130473036482. Its totient is φ = 130473036480.

The previous prime is 130473036413. The next prime is 130473036523. The reversal of 130473036481 is 184630374031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130194680625 + 278355856 = 360825^2 + 16684^2 .

It is a cyclic number.

It is not a de Polignac number, because 130473036481 - 225 = 130439482049 is a prime.

It is a super-2 number, since 2×1304730364812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130473036181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65236518240 + 65236518241.

It is an arithmetic number, because the mean of its divisors is an integer number (65236518241).

Almost surely, 2130473036481 is an apocalyptic number.

It is an amenable number.

130473036481 is a deficient number, since it is larger than the sum of its proper divisors (1).

130473036481 is an equidigital number, since it uses as much as digits as its factorization.

130473036481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 40.

The spelling of 130473036481 in words is "one hundred thirty billion, four hundred seventy-three million, thirty-six thousand, four hundred eighty-one".