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130481167057 is a prime number
BaseRepresentation
bin111100110000101001…
…0001001101011010001
3110110210110100001201221
41321201102021223101
54114211134321212
6135535304125041
712266305422523
oct1714122115321
9413713301657
10130481167057
115037824305a
1221355a66781
13c3c5794777
14645b35ba13
1535da20b807
hex1e61489ad1

130481167057 has 2 divisors, whose sum is σ = 130481167058. Its totient is φ = 130481167056.

The previous prime is 130481166947. The next prime is 130481167099. The reversal of 130481167057 is 750761184031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111184901136 + 19296265921 = 333444^2 + 138911^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130481167057 is a prime.

It is not a weakly prime, because it can be changed into another prime (130481167457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65240583528 + 65240583529.

It is an arithmetic number, because the mean of its divisors is an integer number (65240583529).

Almost surely, 2130481167057 is an apocalyptic number.

It is an amenable number.

130481167057 is a deficient number, since it is larger than the sum of its proper divisors (1).

130481167057 is an equidigital number, since it uses as much as digits as its factorization.

130481167057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 141120, while the sum is 43.

The spelling of 130481167057 in words is "one hundred thirty billion, four hundred eighty-one million, one hundred sixty-seven thousand, fifty-seven".