130495081 has 2 divisors, whose sum is σ = 130495082. Its totient is φ = 130495080.

The previous prime is 130495051. The next prime is 130495109. The reversal of 130495081 is 180594031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121992025 + 8503056 = 11045^2 + 2916^2 .

It is a cyclic number.

It is not a de Polignac number, because 130495081 - 2¹⁵ = 130462313 is a prime.

It is a super-2 number, since 2×130495081² = 34057932330393122, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130495051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65247540 + 65247541.

It is an arithmetic number, because the mean of its divisors is an integer number (65247541).

Almost surely, 2^130495081 is an apocalyptic number.

It is an amenable number.

130495081 is a deficient number, since it is larger than the sum of its proper divisors (1).

130495081 is an equidigital number, since it uses as much as digits as its factorization.

130495081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

The square root of 130495081 is about 11423.4443579859. Note that the first 3 decimals coincide. The cubic root of 130495081 is about 507.2219590503.

It can be divided in two parts, 1304950 and 81, that added together give a palindrome (1305031).

The spelling of 130495081 in words is "one hundred thirty million, four hundred ninety-five thousand, eighty-one".