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130501404653 = 671947782159
BaseRepresentation
bin111100110001001111…
…1010110011111101101
3110110211212102020111112
41321202133112133231
54114231324422103
6135541310001405
712266642431334
oct1714237263755
9413755366445
10130501404653
1150388705944
12213607a6265
13c3c9a2c089
14645dd08d1b
1535dbda7cd8
hex1e627d67ed

130501404653 has 4 divisors (see below), whose sum is σ = 132449186880. Its totient is φ = 128553622428.

The previous prime is 130501404643. The next prime is 130501404701. The reversal of 130501404653 is 356404105031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130501404653 - 218 = 130501142509 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130501404643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 973891013 + ... + 973891146.

It is an arithmetic number, because the mean of its divisors is an integer number (33112296720).

Almost surely, 2130501404653 is an apocalyptic number.

It is an amenable number.

130501404653 is a deficient number, since it is larger than the sum of its proper divisors (1947782227).

130501404653 is an equidigital number, since it uses as much as digits as its factorization.

130501404653 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1947782226.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 130501404653 its reverse (356404105031), we get a palindrome (486905509684).

The spelling of 130501404653 in words is "one hundred thirty billion, five hundred one million, four hundred four thousand, six hundred fifty-three".

Divisors: 1 67 1947782159 130501404653