1305030113 has 2 divisors, whose sum is σ = 1305030114. Its totient is φ = 1305030112.

The previous prime is 1305030053. The next prime is 1305030121. The reversal of 1305030113 is 3110305031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1076627344 + 228402769 = 32812^2 + 15113^2 .

It is an emirp because it is prime and its reverse (3110305031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1305030113 - 2⁶ = 1305030049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1305030091 and 1305030100.

It is not a weakly prime, because it can be changed into another prime (1305030163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652515056 + 652515057.

It is an arithmetic number, because the mean of its divisors is an integer number (652515057).

Almost surely, 2^1305030113 is an apocalyptic number.

It is an amenable number.

1305030113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305030113 is an equidigital number, since it uses as much as digits as its factorization.

1305030113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 1305030113 is about 36125.2005253950. The cubic root of 1305030113 is about 1092.7987200045.

Adding to 1305030113 its reverse (3110305031), we get a palindrome (4415335144).

The spelling of 1305030113 in words is "one billion, three hundred five million, thirty thousand, one hundred thirteen".