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130503433 is a prime number
BaseRepresentation
bin1111100011101…
…01001100001001
3100002120021001111
413301311030021
5231402102213
620541050321
73143155324
oct761651411
9302507044
10130503433
1167736185
12378569a1
1321063988
14134917bb
15b6cca3d
hex7c75309

130503433 has 2 divisors, whose sum is σ = 130503434. Its totient is φ = 130503432.

The previous prime is 130503427. The next prime is 130503481. The reversal of 130503433 is 334305031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75550864 + 54952569 = 8692^2 + 7413^2 .

It is a cyclic number.

It is not a de Polignac number, because 130503433 - 213 = 130495241 is a prime.

It is a super-2 number, since 2×1305034332 = 34062292049570978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130503733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65251716 + 65251717.

It is an arithmetic number, because the mean of its divisors is an integer number (65251717).

Almost surely, 2130503433 is an apocalyptic number.

It is an amenable number.

130503433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130503433 is an equidigital number, since it uses as much as digits as its factorization.

130503433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 22.

The square root of 130503433 is about 11423.8099161357. The cubic root of 130503433 is about 507.2327799624.

Adding to 130503433 its reverse (334305031), we get a palindrome (464808464).

The spelling of 130503433 in words is "one hundred thirty million, five hundred three thousand, four hundred thirty-three".