Search a number
-
+
130523130004154 = 265261565002077
BaseRepresentation
bin11101101011010111001000…
…110011001000001010111010
3122010010220000100101221202212
4131223113020303020022322
5114101442332240113104
61141333255333255122
736330661560316436
oct3553271063101272
9563126010357685
10130523130004154
113865260417a138
12127803101944a2
1357aa3806ac744
1424334d32719c6
151015315b1b36e
hex76b5c8cc82ba

130523130004154 has 4 divisors (see below), whose sum is σ = 195784695006234. Its totient is φ = 65261565002076.

The previous prime is 130523130004153. The next prime is 130523130004171. The reversal of 130523130004154 is 451400031325031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112026877275625 + 18496252728529 = 10584275^2 + 4300727^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 130523130004154.

It is not an unprimeable number, because it can be changed into a prime (130523130004153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32630782501037 + ... + 32630782501040.

Almost surely, 2130523130004154 is an apocalyptic number.

130523130004154 is a deficient number, since it is larger than the sum of its proper divisors (65261565002080).

130523130004154 is an equidigital number, since it uses as much as digits as its factorization.

130523130004154 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65261565002079.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 130523130004154 its reverse (451400031325031), we get a palindrome (581923161329185).

The spelling of 130523130004154 in words is "one hundred thirty trillion, five hundred twenty-three billion, one hundred thirty million, four thousand, one hundred fifty-four".

Divisors: 1 2 65261565002077 130523130004154