Search a number
-
+
1305243344011 is a prime number
BaseRepresentation
bin10010111111100110100…
…100001101110010001011
311121210001122121221000111
4102333212210031302023
5132341114244002021
62435342010415151
7163205101236535
oct22774644156213
94553048557014
101305243344011
11463606927152
12190b6b4314b7
13961124a7c69
1447261ab2855
1523e443e88e1
hex12fe690dc8b

1305243344011 has 2 divisors, whose sum is σ = 1305243344012. Its totient is φ = 1305243344010.

The previous prime is 1305243343973. The next prime is 1305243344081. The reversal of 1305243344011 is 1104433425031.

It is a weak prime.

It is an emirp because it is prime and its reverse (1104433425031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1305243344011 - 29 = 1305243343499 is a prime.

It is not a weakly prime, because it can be changed into another prime (1305243344081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652621672005 + 652621672006.

It is an arithmetic number, because the mean of its divisors is an integer number (652621672006).

Almost surely, 21305243344011 is an apocalyptic number.

1305243344011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305243344011 is an equidigital number, since it uses as much as digits as its factorization.

1305243344011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1305243344011 its reverse (1104433425031), we get a palindrome (2409676769042).

The spelling of 1305243344011 in words is "one trillion, three hundred five billion, two hundred forty-three million, three hundred forty-four thousand, eleven".