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1305252120103 = 3569813656363
BaseRepresentation
bin10010111111100111000…
…101101100011000100111
311121210002021010210112221
4102333213011230120213
5132341124020320403
62435342522453211
7163205235651031
oct22774705543047
94553067123487
101305252120103
11463610880818
12190b72364207
139611425b709
1447262d18c51
1523e4507ddbd
hex12fe716c627

1305252120103 has 4 divisors (see below), whose sum is σ = 1305256133448. Its totient is φ = 1305248106760.

The previous prime is 1305252120101. The next prime is 1305252120157. The reversal of 1305252120103 is 3010212525031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1305252120103 - 21 = 1305252120101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1305252120101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1471201 + ... + 2185162.

It is an arithmetic number, because the mean of its divisors is an integer number (326314033362).

Almost surely, 21305252120103 is an apocalyptic number.

1305252120103 is a deficient number, since it is larger than the sum of its proper divisors (4013345).

1305252120103 is an equidigital number, since it uses as much as digits as its factorization.

1305252120103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4013344.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 1305252120103 its reverse (3010212525031), we get a palindrome (4315464645134).

The spelling of 1305252120103 in words is "one trillion, three hundred five billion, two hundred fifty-two million, one hundred twenty thousand, one hundred three".

Divisors: 1 356981 3656363 1305252120103