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130525537 is a prime number
BaseRepresentation
bin1111100011110…
…10100101100001
3100002121101101011
413301322211201
5231403304122
620541340521
73143306632
oct761724541
9302541334
10130525537
116775084a
1237867741
1321070a5c
1413499889
15b6d4377
hex7c7a961

130525537 has 2 divisors, whose sum is σ = 130525538. Its totient is φ = 130525536.

The previous prime is 130525519. The next prime is 130525583. The reversal of 130525537 is 735525031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113294736 + 17230801 = 10644^2 + 4151^2 .

It is an emirp because it is prime and its reverse (735525031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130525537 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130525499 and 130525508.

It is not a weakly prime, because it can be changed into another prime (130522537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65262768 + 65262769.

It is an arithmetic number, because the mean of its divisors is an integer number (65262769).

Almost surely, 2130525537 is an apocalyptic number.

It is an amenable number.

130525537 is a deficient number, since it is larger than the sum of its proper divisors (1).

130525537 is an equidigital number, since it uses as much as digits as its factorization.

130525537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15750, while the sum is 31.

The square root of 130525537 is about 11424.7773282458. Note that the first 3 decimals coincide. The cubic root of 130525537 is about 507.2614158386.

The spelling of 130525537 in words is "one hundred thirty million, five hundred twenty-five thousand, five hundred thirty-seven".