13053033204053 has 4 divisors (see below), whose sum is σ = 13125955177440. Its totient is φ = 12980111230668.

The previous prime is 13053033204049. The next prime is 13053033204073. The reversal of 13053033204053 is 35040233035031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13053033204053 - 2² = 13053033204049 is a prime.

It is a super-2 number, since 2×13053033204053² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13053033204023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36460986425 + ... + 36460986782.

It is an arithmetic number, because the mean of its divisors is an integer number (3281488794360).

Almost surely, 2^{13053033204053} is an apocalyptic number.

It is an amenable number.

13053033204053 is a deficient number, since it is larger than the sum of its proper divisors (72921973387).

13053033204053 is an equidigital number, since it uses as much as digits as its factorization.

13053033204053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72921973386.

The product of its (nonzero) digits is 48600, while the sum is 32.

Adding to 13053033204053 its reverse (35040233035031), we get a palindrome (48093266239084).

The spelling of 13053033204053 in words is "thirteen trillion, fifty-three billion, thirty-three million, two hundred four thousand, fifty-three".