Base | Representation |
---|---|
bin | 1011110111110010101101… |
… | …1110101111001111010011 |
3 | 1201012212102102112210202121 |
4 | 2331330223132233033103 |
5 | 3202330310040400033 |
6 | 43432305533555111 |
7 | 2515025566412164 |
oct | 275745336571723 |
9 | 51185372483677 |
10 | 13053135090643 |
11 | 418289251184a |
12 | 1569950645a97 |
13 | 738ba00bb25b |
14 | 331abcc8576b |
15 | 17981e3a762d |
hex | bdf2b7af3d3 |
13053135090643 has 2 divisors, whose sum is σ = 13053135090644. Its totient is φ = 13053135090642.
The previous prime is 13053135090607. The next prime is 13053135090661. The reversal of 13053135090643 is 34609053135031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13053135090643 - 213 = 13053135082451 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13053135090643.
It is not a weakly prime, because it can be changed into another prime (13053135090143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526567545321 + 6526567545322.
It is an arithmetic number, because the mean of its divisors is an integer number (6526567545322).
Almost surely, 213053135090643 is an apocalyptic number.
13053135090643 is a deficient number, since it is larger than the sum of its proper divisors (1).
13053135090643 is an equidigital number, since it uses as much as digits as its factorization.
13053135090643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 43.
The spelling of 13053135090643 in words is "thirteen trillion, fifty-three billion, one hundred thirty-five million, ninety thousand, six hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •