Base | Representation |
---|---|
bin | 1011110111110010101101… |
… | …1110110111010001000001 |
3 | 1201012212102102121110212022 |
4 | 2331330223132313101001 |
5 | 3202330310042423041 |
6 | 43432305534411225 |
7 | 2515025566610063 |
oct | 275745336672101 |
9 | 51185372543768 |
10 | 13053135123521 |
11 | 4182892534519 |
12 | 1569950660b15 |
13 | 738ba01001cc |
14 | 331abcc93733 |
15 | 17981e3b224b |
hex | bdf2b7b7441 |
13053135123521 has 2 divisors, whose sum is σ = 13053135123522. Its totient is φ = 13053135123520.
The previous prime is 13053135123401. The next prime is 13053135123547. The reversal of 13053135123521 is 12532153135031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12980967673921 + 72167449600 = 3602911^2 + 268640^2 .
It is a cyclic number.
It is not a de Polignac number, because 13053135123521 - 238 = 12778257216577 is a prime.
It is not a weakly prime, because it can be changed into another prime (13053135123571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526567561760 + 6526567561761.
It is an arithmetic number, because the mean of its divisors is an integer number (6526567561761).
Almost surely, 213053135123521 is an apocalyptic number.
It is an amenable number.
13053135123521 is a deficient number, since it is larger than the sum of its proper divisors (1).
13053135123521 is an equidigital number, since it uses as much as digits as its factorization.
13053135123521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 13053135123521 its reverse (12532153135031), we get a palindrome (25585288258552).
The spelling of 13053135123521 in words is "thirteen trillion, fifty-three billion, one hundred thirty-five million, one hundred twenty-three thousand, five hundred twenty-one".
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