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1305314113 is a prime number
BaseRepresentation
bin100110111001101…
…1000001101000001
310100222011211100011
41031303120031001
510133130022423
6333305224521
744226662335
oct11563301501
93328154304
101305314113
1160a8a78a4
12305192141
1317a578a1c
14c55057c5
15798deb0d
hex4dcd8341

1305314113 has 2 divisors, whose sum is σ = 1305314114. Its totient is φ = 1305314112.

The previous prime is 1305314069. The next prime is 1305314141. The reversal of 1305314113 is 3114135031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1224440064 + 80874049 = 34992^2 + 8993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1305314113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1305314183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652657056 + 652657057.

It is an arithmetic number, because the mean of its divisors is an integer number (652657057).

Almost surely, 21305314113 is an apocalyptic number.

It is an amenable number.

1305314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305314113 is an equidigital number, since it uses as much as digits as its factorization.

1305314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1305314113 is about 36129.1310855935. The cubic root of 1305314113 is about 1092.8779856917.

Adding to 1305314113 its reverse (3114135031), we get a palindrome (4419449144).

The spelling of 1305314113 in words is "one billion, three hundred five million, three hundred fourteen thousand, one hundred thirteen".