Base | Representation |
---|---|
bin | 11000010100000100… |
… | …00110010111111001 |
3 | 1020200200221111200002 |
4 | 30022002012113321 |
5 | 203213111140231 |
6 | 5555131522345 |
7 | 641320401635 |
oct | 141202062771 |
9 | 36620844602 |
10 | 13053224441 |
11 | 55992287a4 |
12 | 26435b93b5 |
13 | 130041895a |
14 | 8bb861dc5 |
15 | 515e670cb |
hex | 30a0865f9 |
13053224441 has 2 divisors, whose sum is σ = 13053224442. Its totient is φ = 13053224440.
The previous prime is 13053224411. The next prime is 13053224473. The reversal of 13053224441 is 14442235031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11930974441 + 1122250000 = 109229^2 + 33500^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13053224441 is a prime.
It is a super-3 number, since 3×130532244413 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13053224411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526612220 + 6526612221.
It is an arithmetic number, because the mean of its divisors is an integer number (6526612221).
Almost surely, 213053224441 is an apocalyptic number.
It is an amenable number.
13053224441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13053224441 is an equidigital number, since it uses as much as digits as its factorization.
13053224441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13053224441 its reverse (14442235031), we get a palindrome (27495459472).
The spelling of 13053224441 in words is "thirteen billion, fifty-three million, two hundred twenty-four thousand, four hundred forty-one".
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