Base | Representation |
---|---|
bin | 10010111111110001101… |
… | …100101111111101000111 |
3 | 11121210112200002122220201 |
4 | 102333301230233331013 |
5 | 132342010103134003 |
6 | 2435412322111331 |
7 | 163212530011552 |
oct | 22776154577507 |
9 | 4553480078821 |
10 | 1305430130503 |
11 | 4636a2304654 |
12 | 191001aab547 |
13 | 961420b6b05 |
14 | 4727c815699 |
15 | 23e559e2b1d |
hex | 12ff1b2ff47 |
1305430130503 has 64 divisors (see below), whose sum is σ = 1430516505600. Its totient is φ = 1187987834880.
The previous prime is 1305430130491. The next prime is 1305430130513. The reversal of 1305430130503 is 3050310345031.
It is a cyclic number.
It is not a de Polignac number, because 1305430130503 - 229 = 1304893259591 is a prime.
It is a super-2 number, since 2×13054301305032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1305430130513) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3115584828 + ... + 3115585246.
It is an arithmetic number, because the mean of its divisors is an integer number (22351820400).
Almost surely, 21305430130503 is an apocalyptic number.
1305430130503 is a deficient number, since it is larger than the sum of its proper divisors (125086375097).
1305430130503 is a wasteful number, since it uses less digits than its factorization.
1305430130503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 952.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 1305430130503 its reverse (3050310345031), we get a palindrome (4355740475534).
The spelling of 1305430130503 in words is "one trillion, three hundred five billion, four hundred thirty million, one hundred thirty thousand, five hundred three".
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