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130544040000 = 263541198897
BaseRepresentation
bin111100110010100000…
…1111111100001000000
3110110221211122100012110
41321211001333201000
54114323233240000
6135545431455320
712301001013543
oct1714501774100
9413854570173
10130544040000
11503aa786470
1221372b27540
13c4058092aa
14646584685a
1535e09ca850
hex1e6507f840

130544040000 has 280 divisors, whose sum is σ = 470851004448. Its totient is φ = 31646720000.

The previous prime is 130544039971. The next prime is 130544040013. The reversal of 130544040000 is 40445031.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1270552 + ... + 1369448.

Almost surely, 2130544040000 is an apocalyptic number.

130544040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130544040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (235425502224).

130544040000 is an abundant number, since it is smaller than the sum of its proper divisors (340306964448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130544040000 is an equidigital number, since it uses as much as digits as its factorization.

130544040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98943 (or 98918 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 21.

Adding to 130544040000 its reverse (40445031), we get a palindrome (130584485031).

The spelling of 130544040000 in words is "one hundred thirty billion, five hundred forty-four million, forty thousand".