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13054405120534 = 26691975519737
BaseRepresentation
bin1011110111110111011100…
…1011100001001000010110
31201012222200221100000020201
42331331313023201020112
53202340410202324114
643433035543051114
72515102220450221
oct275756713411026
951188627300221
1013054405120534
1141833843aa028
12156a045a40a9a
13739043261a2b
14331b9d8045b8
15179895b27874
hexbdf772e1216

13054405120534 has 8 divisors (see below), whose sum is σ = 19584534260088. Its totient is φ = 6526227033840.

The previous prime is 13054405120513. The next prime is 13054405120541. The reversal of 13054405120534 is 43502150445031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13054405120493 and 13054405120502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 487746487 + ... + 487773250.

It is an arithmetic number, because the mean of its divisors is an integer number (2448066782511).

Almost surely, 213054405120534 is an apocalyptic number.

13054405120534 is a deficient number, since it is larger than the sum of its proper divisors (6530129139554).

13054405120534 is an equidigital number, since it uses as much as digits as its factorization.

13054405120534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 975526430.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 13054405120534 its reverse (43502150445031), we get a palindrome (56556555565565).

The spelling of 13054405120534 in words is "thirteen trillion, fifty-four billion, four hundred five million, one hundred twenty thousand, five hundred thirty-four".

Divisors: 1 2 6691 13382 975519737 1951039474 6527202560267 13054405120534