Base | Representation |
---|---|
bin | 11101101011101010111110… |
… | …101001010111101011011011 |
3 | 122010012221000002121000101111 |
4 | 131223222332221113223123 |
5 | 114102320000213314210 |
6 | 1141351141343001151 |
7 | 36332344532533132 |
oct | 3553527651275333 |
9 | 563187002530344 |
10 | 130544434510555 |
11 | 38660646aa411a |
12 | 12784476b991b7 |
13 | 57ac39740c550 |
14 | 24345548cc919 |
15 | 1015b6116788a |
hex | 76babea57adb |
130544434510555 has 64 divisors (see below), whose sum is σ = 173929257452160. Its totient is φ = 93460531507200.
The previous prime is 130544434510517. The next prime is 130544434510597. The reversal of 130544434510555 is 555015434445031.
It is a de Polignac number, because none of the positive numbers 2k-130544434510555 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130544434510499 and 130544434510508.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 481540945 + ... + 481811965.
It is an arithmetic number, because the mean of its divisors is an integer number (2717644647690).
Almost surely, 2130544434510555 is an apocalyptic number.
130544434510555 is a deficient number, since it is larger than the sum of its proper divisors (43384822941605).
130544434510555 is a wasteful number, since it uses less digits than its factorization.
130544434510555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 272752.
The product of its (nonzero) digits is 7200000, while the sum is 49.
Adding to 130544434510555 its reverse (555015434445031), we get a palindrome (685559868955586).
The spelling of 130544434510555 in words is "one hundred thirty trillion, five hundred forty-four billion, four hundred thirty-four million, five hundred ten thousand, five hundred fifty-five".
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