Base | Representation |
---|---|
bin | 10010111111110010100… |
… | …111000111100000001000 |
3 | 11121210120201220000200001 |
4 | 102333302213013200020 |
5 | 132342023012300204 |
6 | 2435414030052344 |
7 | 163213104036400 |
oct | 22776247074010 |
9 | 4553521800601 |
10 | 1305445431304 |
11 | 4636aaa05343 |
12 | 19100704a0b4 |
13 | 96145313341 |
14 | 47280879800 |
15 | 23e570164a4 |
hex | 12ff29c7808 |
1305445431304 has 24 divisors (see below), whose sum is σ = 2847336336990. Its totient is φ = 559476613248.
The previous prime is 1305445431289. The next prime is 1305445431343. The reversal of 1305445431304 is 4031345445031.
It can be written as a sum of positive squares in only one way, i.e., 1122434302500 + 183011128804 = 1059450^2 + 427798^2 .
It is a super-2 number, since 2×13054454313042 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1665108577 + ... + 1665109360.
Almost surely, 21305445431304 is an apocalyptic number.
1305445431304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1305445431304 is an abundant number, since it is smaller than the sum of its proper divisors (1541890905686).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305445431304 is a wasteful number, since it uses less digits than its factorization.
1305445431304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3330217957 (or 3330217946 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 37.
The spelling of 1305445431304 in words is "one trillion, three hundred five billion, four hundred forty-five million, four hundred thirty-one thousand, three hundred four".
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