Search a number
-
+
13054511232000 = 21033537539621
BaseRepresentation
bin1011110111110111110110…
…0000010011010000000000
31201012222222100000000211000
42331331331200103100000
53202341114333411000
643433054253252000
72515104646415130
oct275757540232000
951188870000730
1013054511232000
114183429295157
12156a075494000
1373905c235194
14331bad946ac0
151798a00d8000
hexbdf7d813400

13054511232000 has 704 divisors, whose sum is σ = 55141943201280. Its totient is φ = 2983882752000.

The previous prime is 13054511231989. The next prime is 13054511232001. The reversal of 13054511232000 is 23211545031.

13054511232000 is a `hidden beast` number, since 1 + 3 + 0 + 5 + 451 + 1 + 2 + 3 + 200 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13054511232001) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23922190 + ... + 24461810.

Almost surely, 213054511232000 is an apocalyptic number.

13054511232000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13054511232000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27570971600640).

13054511232000 is an abundant number, since it is smaller than the sum of its proper divisors (42087431969280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13054511232000 is an equidigital number, since it uses as much as digits as its factorization.

13054511232000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 539672 (or 539638 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 13054511232000 its reverse (23211545031), we get a palindrome (13077722777031).

The spelling of 13054511232000 in words is "thirteen trillion, fifty-four billion, five hundred eleven million, two hundred thirty-two thousand".