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13054556653009 is a prime number
BaseRepresentation
bin1011110111111000000000…
…1101100100010111010001
31201020000002111110122201121
42331332000031210113101
53202341213000344014
643433102555002241
72515106040451654
oct275760015442721
951200074418647
1013054556653009
114183451998683
12156a088739381
13739068779311
14331bb59ab89b
151798a40ab124
hexbdf803645d1

13054556653009 has 2 divisors, whose sum is σ = 13054556653010. Its totient is φ = 13054556653008.

The previous prime is 13054556653001. The next prime is 13054556653037. The reversal of 13054556653009 is 90035665545031.

13054556653009 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6736230930625 + 6318325722384 = 2595425^2 + 2513628^2 .

It is an emirp because it is prime and its reverse (90035665545031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13054556653009 - 23 = 13054556653001 is a prime.

It is not a weakly prime, because it can be changed into another prime (13054556653001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527278326504 + 6527278326505.

It is an arithmetic number, because the mean of its divisors is an integer number (6527278326505).

Almost surely, 213054556653009 is an apocalyptic number.

It is an amenable number.

13054556653009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13054556653009 is an equidigital number, since it uses as much as digits as its factorization.

13054556653009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290000, while the sum is 52.

The spelling of 13054556653009 in words is "thirteen trillion, fifty-four billion, five hundred fifty-six million, six hundred fifty-three thousand, nine".