Base | Representation |
---|---|
bin | 11101101011101100000011… |
… | …111101111101100100010011 |
3 | 122010020001000011000212002122 |
4 | 131223230003331331210103 |
5 | 114102324340432132111 |
6 | 1141351453010404455 |
7 | 36332415414225332 |
oct | 3553540375754423 |
9 | 563201004025078 |
10 | 130545597536531 |
11 | 38661093546811 |
12 | 1278474059072b |
13 | 57ac5213595b8 |
14 | 2434625155d19 |
15 | 1015bcd2eccdb |
hex | 76bb03f7d913 |
130545597536531 has 2 divisors, whose sum is σ = 130545597536532. Its totient is φ = 130545597536530.
The previous prime is 130545597536527. The next prime is 130545597536537. The reversal of 130545597536531 is 135635795545031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130545597536531 - 22 = 130545597536527 is a prime.
It is a super-2 number, since 2×1305455975365312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130545597536537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65272798768265 + 65272798768266.
It is an arithmetic number, because the mean of its divisors is an integer number (65272798768266).
Almost surely, 2130545597536531 is an apocalyptic number.
130545597536531 is a deficient number, since it is larger than the sum of its proper divisors (1).
130545597536531 is an equidigital number, since it uses as much as digits as its factorization.
130545597536531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 127575000, while the sum is 62.
The spelling of 130545597536531 in words is "one hundred thirty trillion, five hundred forty-five billion, five hundred ninety-seven million, five hundred thirty-six thousand, five hundred thirty-one".
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