Base | Representation |
---|---|
bin | 1011110111111000001110… |
… | …0001010010010011001111 |
3 | 1201020000020100220101011020 |
4 | 2331332003201102103033 |
5 | 3202341321202403201 |
6 | 43433112300325223 |
7 | 2515110313266063 |
oct | 275760341222317 |
9 | 51200210811136 |
10 | 13054612153551 |
11 | 4183480255aa1 |
12 | 156a0a3243813 |
13 | 73907710c287 |
14 | 331bbd0d7aa3 |
15 | 1798a8dc0a36 |
hex | bdf838524cf |
13054612153551 has 4 divisors (see below), whose sum is σ = 17406149538072. Its totient is φ = 8703074769032.
The previous prime is 13054612153469. The next prime is 13054612153589. The reversal of 13054612153551 is 15535121645031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13054612153551 - 222 = 13054607959247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13054612153151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2175768692256 + ... + 2175768692261.
It is an arithmetic number, because the mean of its divisors is an integer number (4351537384518).
Almost surely, 213054612153551 is an apocalyptic number.
13054612153551 is a deficient number, since it is larger than the sum of its proper divisors (4351537384521).
13054612153551 is an equidigital number, since it uses as much as digits as its factorization.
13054612153551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4351537384520.
The product of its (nonzero) digits is 270000, while the sum is 42.
Adding to 13054612153551 its reverse (15535121645031), we get a palindrome (28589733798582).
The spelling of 13054612153551 in words is "thirteen trillion, fifty-four billion, six hundred twelve million, one hundred fifty-three thousand, five hundred fifty-one".
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