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13054612153551 = 34351537384517
BaseRepresentation
bin1011110111111000001110…
…0001010010010011001111
31201020000020100220101011020
42331332003201102103033
53202341321202403201
643433112300325223
72515110313266063
oct275760341222317
951200210811136
1013054612153551
114183480255aa1
12156a0a3243813
1373907710c287
14331bbd0d7aa3
151798a8dc0a36
hexbdf838524cf

13054612153551 has 4 divisors (see below), whose sum is σ = 17406149538072. Its totient is φ = 8703074769032.

The previous prime is 13054612153469. The next prime is 13054612153589. The reversal of 13054612153551 is 15535121645031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13054612153551 - 222 = 13054607959247 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13054612153151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2175768692256 + ... + 2175768692261.

It is an arithmetic number, because the mean of its divisors is an integer number (4351537384518).

Almost surely, 213054612153551 is an apocalyptic number.

13054612153551 is a deficient number, since it is larger than the sum of its proper divisors (4351537384521).

13054612153551 is an equidigital number, since it uses as much as digits as its factorization.

13054612153551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4351537384520.

The product of its (nonzero) digits is 270000, while the sum is 42.

Adding to 13054612153551 its reverse (15535121645031), we get a palindrome (28589733798582).

The spelling of 13054612153551 in words is "thirteen trillion, fifty-four billion, six hundred twelve million, one hundred fifty-three thousand, five hundred fifty-one".

Divisors: 1 3 4351537384517 13054612153551