Base | Representation |
---|---|
bin | 1011110111111000001110… |
… | …0001010010010011010000 |
3 | 1201020000020100220101011021 |
4 | 2331332003201102103100 |
5 | 3202341321202403202 |
6 | 43433112300325224 |
7 | 2515110313266064 |
oct | 275760341222320 |
9 | 51200210811137 |
10 | 13054612153552 |
11 | 4183480255aa2 |
12 | 156a0a3243814 |
13 | 73907710c288 |
14 | 331bbd0d7aa4 |
15 | 1798a8dc0a37 |
hex | bdf838524d0 |
13054612153552 has 10 divisors (see below), whose sum is σ = 25293311047538. Its totient is φ = 6527306076768.
The previous prime is 13054612153469. The next prime is 13054612153589. The reversal of 13054612153552 is 25535121645031.
It can be written as a sum of positive squares in only one way, i.e., 13053653384256 + 958769296 = 3612984^2 + 30964^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13054612153499 and 13054612153508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 407956629783 + ... + 407956629814.
Almost surely, 213054612153552 is an apocalyptic number.
It is an amenable number.
13054612153552 is a deficient number, since it is larger than the sum of its proper divisors (12238698893986).
13054612153552 is an equidigital number, since it uses as much as digits as its factorization.
13054612153552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 815913259605 (or 815913259599 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 43.
Adding to 13054612153552 its reverse (25535121645031), we get a palindrome (38589733798583).
The spelling of 13054612153552 in words is "thirteen trillion, fifty-four billion, six hundred twelve million, one hundred fifty-three thousand, five hundred fifty-two".
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