Base | Representation |
---|---|
bin | 10010111111110110100… |
… | …010000101111111000010 |
3 | 11121210202022200121020012 |
4 | 102333312202011333002 |
5 | 132342141333120414 |
6 | 2435424340144522 |
7 | 163214533205531 |
oct | 22776642057702 |
9 | 4553668617205 |
10 | 1305511223234 |
11 | 463734061839 |
12 | 191025098142 |
13 | 96155b3a68a |
14 | 472894c4318 |
15 | 23e5cbb033e |
hex | 12ff6885fc2 |
1305511223234 has 4 divisors (see below), whose sum is σ = 1958266834854. Its totient is φ = 652755611616.
The previous prime is 1305511223143. The next prime is 1305511223249. The reversal of 1305511223234 is 4323221155031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 714865177009 + 590646046225 = 845497^2 + 768535^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1305511223234.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326377805807 + ... + 326377805810.
Almost surely, 21305511223234 is an apocalyptic number.
1305511223234 is a deficient number, since it is larger than the sum of its proper divisors (652755611620).
1305511223234 is an equidigital number, since it uses as much as digits as its factorization.
1305511223234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 652755611619.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1305511223234 its reverse (4323221155031), we get a palindrome (5628732378265).
The spelling of 1305511223234 in words is "one trillion, three hundred five billion, five hundred eleven million, two hundred twenty-three thousand, two hundred thirty-four".
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