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130551142143 = 3123953351077
BaseRepresentation
bin111100110010101110…
…1000101011011111111
3110110222100000011111210
41321211131011123333
54114332043022033
6135550244015503
712301115253522
oct1714535053377
9413870004453
10130551142143
1150403797404
1221375391593
13c407124b46
146466774bb9
1535e142ed63
hex1e657456ff

130551142143 has 8 divisors (see below), whose sum is σ = 174070089648. Its totient is φ = 87033144704.

The previous prime is 130551142063. The next prime is 130551142153. The reversal of 130551142143 is 341241155031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130551142143 - 29 = 130551141631 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130551142143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130551142153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 196321 + ... + 547397.

It is an arithmetic number, because the mean of its divisors is an integer number (21758761206).

Almost surely, 2130551142143 is an apocalyptic number.

130551142143 is a deficient number, since it is larger than the sum of its proper divisors (43518947505).

130551142143 is a wasteful number, since it uses less digits than its factorization.

130551142143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 475033.

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 130551142143 its reverse (341241155031), we get a palindrome (471792297174).

The spelling of 130551142143 in words is "one hundred thirty billion, five hundred fifty-one million, one hundred forty-two thousand, one hundred forty-three".

Divisors: 1 3 123953 351077 371859 1053231 43517047381 130551142143