Base | Representation |
---|---|
bin | 11101101011110001110001… |
… | …000000001010001101010110 |
3 | 122010020121210221220111022122 |
4 | 131223301301000022031112 |
5 | 114102424411234441223 |
6 | 1141354344422455542 |
7 | 36333023240456435 |
oct | 3553616100121526 |
9 | 563217727814278 |
10 | 130551721796438 |
11 | 38663746528938 |
12 | 1278596b5945b2 |
13 | 57acc890b1227 |
14 | 2434a4666d11c |
15 | 1015e3accd5c8 |
hex | 76bc7100a356 |
130551721796438 has 8 divisors (see below), whose sum is σ = 202580257960080. Its totient is φ = 63024969143080.
The previous prime is 130551721796371. The next prime is 130551721796453. The reversal of 130551721796438 is 834697127155031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125445877498 + ... + 1125445877613.
It is an arithmetic number, because the mean of its divisors is an integer number (25322532245010).
It is a 2-persistent number, because it is pandigital, and so is 2⋅130551721796438 = 261103443592876, but 3⋅130551721796438 = 391655165389314 is not.
Almost surely, 2130551721796438 is an apocalyptic number.
130551721796438 is a deficient number, since it is larger than the sum of its proper divisors (72028536163642).
130551721796438 is a wasteful number, since it uses less digits than its factorization.
130551721796438 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2250891755142.
The product of its (nonzero) digits is 38102400, while the sum is 62.
The spelling of 130551721796438 in words is "one hundred thirty trillion, five hundred fifty-one billion, seven hundred twenty-one million, seven hundred ninety-six thousand, four hundred thirty-eight".
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