Base | Representation |
---|---|
bin | 11101101011110010001000… |
… | …011010000001101010000101 |
3 | 122010020122211022202112000220 |
4 | 131223302020122001222011 |
5 | 114102431212300000000 |
6 | 1141354451410454553 |
7 | 36333036046135221 |
oct | 3553621032015205 |
9 | 563218738675026 |
10 | 130552114453125 |
11 | 386639281386a2 |
12 | 12785a5ab94459 |
13 | 57b001c551271 |
14 | 2434a82881781 |
15 | 1015e604e11a0 |
hex | 76bc88681a85 |
130552114453125 has 36 divisors (see below), whose sum is σ = 217586747970528. Its totient is φ = 69627793750000.
The previous prime is 130552114453069. The next prime is 130552114453127. The reversal of 130552114453125 is 521354411255031.
It is not a de Polignac number, because 130552114453125 - 27 = 130552114452997 is a prime.
It is a super-3 number, since 3×1305521144531253 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130552114453127) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 54530361 + ... + 56874110.
Almost surely, 2130552114453125 is an apocalyptic number.
130552114453125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
130552114453125 is a deficient number, since it is larger than the sum of its proper divisors (87034633517403).
130552114453125 is an frugal number, since it uses more digits than its factorization.
130552114453125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111404514 (or 111404479 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 130552114453125 in words is "one hundred thirty trillion, five hundred fifty-two billion, one hundred fourteen million, four hundred fifty-three thousand, one hundred twenty-five".
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