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130553250193 is a prime number
BaseRepresentation
bin111100110010110010…
…1001000000110010001
3110110222110222021012201
41321211211020012101
54114333113001233
6135550401123201
712301142213452
oct1714545100621
9413873867181
10130553250193
11504049a71a3
1221376029501
13c4076b2502
146466b63129
1535e16e977d
hex1e65948191

130553250193 has 2 divisors, whose sum is σ = 130553250194. Its totient is φ = 130553250192.

The previous prime is 130553250181. The next prime is 130553250199. The reversal of 130553250193 is 391052355031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102264364944 + 28288885249 = 319788^2 + 168193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130553250193 is a prime.

It is a super-2 number, since 2×1305532501932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130553250199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276625096 + 65276625097.

It is an arithmetic number, because the mean of its divisors is an integer number (65276625097).

Almost surely, 2130553250193 is an apocalyptic number.

It is an amenable number.

130553250193 is a deficient number, since it is larger than the sum of its proper divisors (1).

130553250193 is an equidigital number, since it uses as much as digits as its factorization.

130553250193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60750, while the sum is 37.

The spelling of 130553250193 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred fifty thousand, one hundred ninety-three".