Base | Representation |
---|---|
bin | 1011110111111011001101… |
… | …0000101101111001001011 |
3 | 1201020002022012001111202022 |
4 | 2331332303100231321023 |
5 | 3202344441224211431 |
6 | 43433323551555055 |
7 | 2515136210333024 |
oct | 275766320557113 |
9 | 51202265044668 |
10 | 13055413116491 |
11 | 4183851394339 |
12 | 156a28752ba8b |
13 | 73917403b545 |
14 | 331c57633c4b |
15 | 17990438807b |
hex | bdfb342de4b |
13055413116491 has 2 divisors, whose sum is σ = 13055413116492. Its totient is φ = 13055413116490.
The previous prime is 13055413116409. The next prime is 13055413116623. The reversal of 13055413116491 is 19461131455031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13055413116491 - 222 = 13055408922187 is a prime.
It is not a weakly prime, because it can be changed into another prime (13055413116401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527706558245 + 6527706558246.
It is an arithmetic number, because the mean of its divisors is an integer number (6527706558246).
Almost surely, 213055413116491 is an apocalyptic number.
13055413116491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13055413116491 is an equidigital number, since it uses as much as digits as its factorization.
13055413116491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 44.
The spelling of 13055413116491 in words is "thirteen trillion, fifty-five billion, four hundred thirteen million, one hundred sixteen thousand, four hundred ninety-one".
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