Base | Representation |
---|---|
bin | 111100110010110111… |
… | …0101111001001111011 |
3 | 110110222122201021000011 |
4 | 1321211232233021323 |
5 | 4114334234110332 |
6 | 135550531122351 |
7 | 12301202505334 |
oct | 1714556571173 |
9 | 413878637004 |
10 | 130555769467 |
11 | 50406367a42 |
12 | 21376a433b7 |
13 | c4080850c6 |
14 | 646721b28b |
15 | 35e1a45e47 |
hex | 1e65baf27b |
130555769467 has 2 divisors, whose sum is σ = 130555769468. Its totient is φ = 130555769466.
The previous prime is 130555769411. The next prime is 130555769473. The reversal of 130555769467 is 764967555031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130555769467 - 219 = 130555245179 is a prime.
It is a super-2 number, since 2×1305557694672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130555769867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65277884733 + 65277884734.
It is an arithmetic number, because the mean of its divisors is an integer number (65277884734).
Almost surely, 2130555769467 is an apocalyptic number.
130555769467 is a deficient number, since it is larger than the sum of its proper divisors (1).
130555769467 is an equidigital number, since it uses as much as digits as its factorization.
130555769467 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23814000, while the sum is 58.
The spelling of 130555769467 in words is "one hundred thirty billion, five hundred fifty-five million, seven hundred sixty-nine thousand, four hundred sixty-seven".
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