Base | Representation |
---|---|
bin | 11000010100010110… |
… | …01001111000010001 |
3 | 1020200212102002201021 |
4 | 30022023021320101 |
5 | 203214213114342 |
6 | 5555254435441 |
7 | 641346516133 |
oct | 141213117021 |
9 | 36625362637 |
10 | 13055598097 |
11 | 559a5aa0a3 |
12 | 2644362b81 |
13 | 1300a6a199 |
14 | 8bbcbd053 |
15 | 516285567 |
hex | 30a2c9e11 |
13055598097 has 2 divisors, whose sum is σ = 13055598098. Its totient is φ = 13055598096.
The previous prime is 13055598029. The next prime is 13055598113. The reversal of 13055598097 is 79089555031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6997155201 + 6058442896 = 83649^2 + 77836^2 .
It is an emirp because it is prime and its reverse (79089555031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13055598097 - 211 = 13055596049 is a prime.
It is not a weakly prime, because it can be changed into another prime (13055595097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527799048 + 6527799049.
It is an arithmetic number, because the mean of its divisors is an integer number (6527799049).
Almost surely, 213055598097 is an apocalyptic number.
It is an amenable number.
13055598097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13055598097 is an equidigital number, since it uses as much as digits as its factorization.
13055598097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701000, while the sum is 52.
The spelling of 13055598097 in words is "thirteen billion, fifty-five million, five hundred ninety-eight thousand, ninety-seven".
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