Base | Representation |
---|---|
bin | 10010111111111100110… |
… | …011001011001110100001 |
3 | 11121211000122112022212021 |
4 | 102333330303023032201 |
5 | 132342400242130244 |
6 | 2435443013501441 |
7 | 163220250662635 |
oct | 22777463131641 |
9 | 4554018468767 |
10 | 1305616364449 |
11 | 463788444a01 |
12 | 191054341881 |
13 | 96171861307 |
14 | 47299452dc5 |
15 | 23e6702d284 |
hex | 12ffcccb3a1 |
1305616364449 has 2 divisors, whose sum is σ = 1305616364450. Its totient is φ = 1305616364448.
The previous prime is 1305616364389. The next prime is 1305616364467. The reversal of 1305616364449 is 9444636165031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1188143600400 + 117472764049 = 1090020^2 + 342743^2 .
It is a cyclic number.
It is not a de Polignac number, because 1305616364449 - 27 = 1305616364321 is a prime.
It is a super-2 number, since 2×13056163644492 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1305616364396 and 1305616364405.
It is not a weakly prime, because it can be changed into another prime (1305616364849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652808182224 + 652808182225.
It is an arithmetic number, because the mean of its divisors is an integer number (652808182225).
Almost surely, 21305616364449 is an apocalyptic number.
It is an amenable number.
1305616364449 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305616364449 is an equidigital number, since it uses as much as digits as its factorization.
1305616364449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5598720, while the sum is 52.
The spelling of 1305616364449 in words is "one trillion, three hundred five billion, six hundred sixteen million, three hundred sixty-four thousand, four hundred forty-nine".
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