Base | Representation |
---|---|
bin | 10011000000011001101… |
… | …001000101111001000001 |
3 | 11121212021101001210100011 |
4 | 103000121221011321001 |
5 | 132344343131313132 |
6 | 2440003021224521 |
7 | 163235245015231 |
oct | 23003151057101 |
9 | 4555241053304 |
10 | 1306100260417 |
11 | 463a06602127 |
12 | 19116a402141 |
13 | 9621ab983a4 |
14 | 47303815cc1 |
15 | 23e94764b47 |
hex | 13019a45e41 |
1306100260417 has 2 divisors, whose sum is σ = 1306100260418. Its totient is φ = 1306100260416.
The previous prime is 1306100260403. The next prime is 1306100260453. The reversal of 1306100260417 is 7140620016031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1275546618801 + 30553641616 = 1129401^2 + 174796^2 .
It is a cyclic number.
It is not a de Polignac number, because 1306100260417 - 219 = 1306099736129 is a prime.
It is a super-2 number, since 2×13061002604172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1306100263417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653050130208 + 653050130209.
It is an arithmetic number, because the mean of its divisors is an integer number (653050130209).
Almost surely, 21306100260417 is an apocalyptic number.
It is an amenable number.
1306100260417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1306100260417 is an equidigital number, since it uses as much as digits as its factorization.
1306100260417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1306100260417 its reverse (7140620016031), we get a palindrome (8446720276448).
The spelling of 1306100260417 in words is "one trillion, three hundred six billion, one hundred million, two hundred sixty thousand, four hundred seventeen".
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