1306112111497 has 2 divisors, whose sum is σ = 1306112111498. Its totient is φ = 1306112111496.

The previous prime is 1306112111449. The next prime is 1306112111501. The reversal of 1306112111497 is 7941112116031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1222607872656 + 83504238841 = 1105716^2 + 288971^2 .

It is a cyclic number.

It is not a de Polignac number, because 1306112111497 - 2¹⁵ = 1306112078729 is a prime.

It is a super-3 number, since 3×1306112111497³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1306112111407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653056055748 + 653056055749.

It is an arithmetic number, because the mean of its divisors is an integer number (653056055749).

Almost surely, 2^{1306112111497} is an apocalyptic number.

It is an amenable number.

1306112111497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1306112111497 is an equidigital number, since it uses as much as digits as its factorization.

1306112111497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 37.

The spelling of 1306112111497 in words is "one trillion, three hundred six billion, one hundred twelve million, one hundred eleven thousand, four hundred ninety-seven".