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1306422513833 is a prime number
BaseRepresentation
bin10011000000101100110…
…110011001000010101001
311121220002211102221220212
4103000230312121002221
5132401023130420313
62440055012230505
7163246240100453
oct23005466310251
94556084387825
101306422513833
114640614a5968
1219123a30b435
139626c888198
144733453d2d3
1523eb2bbc3a8
hex1302cd990a9

1306422513833 has 2 divisors, whose sum is σ = 1306422513834. Its totient is φ = 1306422513832.

The previous prime is 1306422513827. The next prime is 1306422513841. The reversal of 1306422513833 is 3383152246031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 826557359104 + 479865154729 = 909152^2 + 692723^2 .

It is a cyclic number.

It is not a de Polignac number, because 1306422513833 - 28 = 1306422513577 is a prime.

It is a super-3 number, since 3×13064225138333 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1306422513733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653211256916 + 653211256917.

It is an arithmetic number, because the mean of its divisors is an integer number (653211256917).

Almost surely, 21306422513833 is an apocalyptic number.

It is an amenable number.

1306422513833 is a deficient number, since it is larger than the sum of its proper divisors (1).

1306422513833 is an equidigital number, since it uses as much as digits as its factorization.

1306422513833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 41.

Adding to 1306422513833 its reverse (3383152246031), we get a palindrome (4689574759864).

The spelling of 1306422513833 in words is "one trillion, three hundred six billion, four hundred twenty-two million, five hundred thirteen thousand, eight hundred thirty-three".