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130651655243 is a prime number
BaseRepresentation
bin111100110101101110…
…0100000110001001011
3110111020100010202120012
41321223130200301023
54120033310431433
6140004234222135
712303445513604
oct1715334406113
9414210122505
10130651655243
11504554a938a
12213a2b8494b
13c421bb8055
146475c5adab
1535ea186848
hex1e6b720c4b

130651655243 has 2 divisors, whose sum is σ = 130651655244. Its totient is φ = 130651655242.

The previous prime is 130651655203. The next prime is 130651655261. The reversal of 130651655243 is 342556156031.

It is a strong prime.

It is an emirp because it is prime and its reverse (342556156031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130651655243 - 26 = 130651655179 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130651655243.

It is not a weakly prime, because it can be changed into another prime (130651655203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65325827621 + 65325827622.

It is an arithmetic number, because the mean of its divisors is an integer number (65325827622).

Almost surely, 2130651655243 is an apocalyptic number.

130651655243 is a deficient number, since it is larger than the sum of its proper divisors (1).

130651655243 is an equidigital number, since it uses as much as digits as its factorization.

130651655243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 130651655243 in words is "one hundred thirty billion, six hundred fifty-one million, six hundred fifty-five thousand, two hundred forty-three".