Base | Representation |
---|---|
bin | 111100110110001011… |
… | …1111011100001100111 |
3 | 110111021102110002221111 |
4 | 1321230113323201213 |
5 | 4120101302400320 |
6 | 140005552125451 |
7 | 12304025066134 |
oct | 1715427734147 |
9 | 414242402844 |
10 | 130667231335 |
11 | 50463277993 |
12 | 213a8236887 |
13 | c4251ac984 |
14 | 6477d5358b |
15 | 35eb711a5a |
hex | 1e6c5fb867 |
130667231335 has 4 divisors (see below), whose sum is σ = 156800677608. Its totient is φ = 104533785064.
The previous prime is 130667231309. The next prime is 130667231339. The reversal of 130667231335 is 533132766031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130667231335 - 213 = 130667223143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130667231339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13066723129 + ... + 13066723138.
It is an arithmetic number, because the mean of its divisors is an integer number (39200169402).
Almost surely, 2130667231335 is an apocalyptic number.
130667231335 is a deficient number, since it is larger than the sum of its proper divisors (26133446273).
130667231335 is an equidigital number, since it uses as much as digits as its factorization.
130667231335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26133446272.
The product of its (nonzero) digits is 204120, while the sum is 40.
Adding to 130667231335 its reverse (533132766031), we get a palindrome (663799997366).
The spelling of 130667231335 in words is "one hundred thirty billion, six hundred sixty-seven million, two hundred thirty-one thousand, three hundred thirty-five".
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