Base | Representation |
---|---|
bin | 111100110110101000… |
… | …1111011000000100011 |
3 | 110111022111001110111021 |
4 | 1321231101323000203 |
5 | 4120114200333241 |
6 | 140011254030311 |
7 | 12304301233414 |
oct | 1715521730043 |
9 | 414274043437 |
10 | 130682433571 |
11 | 50470910618 |
12 | 213b1348397 |
13 | c4283a3391 |
14 | 6479d8d80b |
15 | 35ecc160d1 |
hex | 1e6d47b023 |
130682433571 has 2 divisors, whose sum is σ = 130682433572. Its totient is φ = 130682433570.
The previous prime is 130682433547. The next prime is 130682433613. The reversal of 130682433571 is 175334286031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130682433571 - 215 = 130682400803 is a prime.
It is not a weakly prime, because it can be changed into another prime (130682433971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65341216785 + 65341216786.
It is an arithmetic number, because the mean of its divisors is an integer number (65341216786).
Almost surely, 2130682433571 is an apocalyptic number.
130682433571 is a deficient number, since it is larger than the sum of its proper divisors (1).
130682433571 is an equidigital number, since it uses as much as digits as its factorization.
130682433571 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 130682433571 in words is "one hundred thirty billion, six hundred eighty-two million, four hundred thirty-three thousand, five hundred seventy-one".
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